-2(8v-4)+8v=6(v+2)

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Solution for -2(8v-4)+8v=6(v+2) equation: 



-2(8v-4)+8v=6(v+2)

We move all terms to the left:

-2(8v-4)+8v-(6(v+2))=0

We add all the numbers together, and all the variables

8v-2(8v-4)-(6(v+2))=0

We multiply parentheses

8v-16v-(6(v+2))+8=0



We calculate terms in parentheses: -(6(v+2)), so:

6(v+2)

We multiply parentheses

6v+12

Back to the equation:

-(6v+12)



We add all the numbers together, and all the variables

-8v-(6v+12)+8=0

We get rid of parentheses

-8v-6v-12+8=0

We add all the numbers together, and all the variables

-14v-4=0

We move all terms containing v to the left, all other terms to the right

-14v=4

v=4/-14

v=-2/7

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