-2(8x-4)+4x=6(x+2)

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Solution for -2(8x-4)+4x=6(x+2) equation: 



-2(8x-4)+4x=6(x+2)

We move all terms to the left:

-2(8x-4)+4x-(6(x+2))=0

We add all the numbers together, and all the variables

4x-2(8x-4)-(6(x+2))=0

We multiply parentheses

4x-16x-(6(x+2))+8=0



We calculate terms in parentheses: -(6(x+2)), so:

6(x+2)

We multiply parentheses

6x+12

Back to the equation:

-(6x+12)



We add all the numbers together, and all the variables

-12x-(6x+12)+8=0

We get rid of parentheses

-12x-6x-12+8=0

We add all the numbers together, and all the variables

-18x-4=0

We move all terms containing x to the left, all other terms to the right

-18x=4

x=4/-18

x=-2/9

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