-2(8y-1)+2y=2(y+3)

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Solution for -2(8y-1)+2y=2(y+3) equation: 



-2(8y-1)+2y=2(y+3)

We move all terms to the left:

-2(8y-1)+2y-(2(y+3))=0

We add all the numbers together, and all the variables

2y-2(8y-1)-(2(y+3))=0

We multiply parentheses

2y-16y-(2(y+3))+2=0



We calculate terms in parentheses: -(2(y+3)), so:

2(y+3)

We multiply parentheses

2y+6

Back to the equation:

-(2y+6)



We add all the numbers together, and all the variables

-14y-(2y+6)+2=0

We get rid of parentheses

-14y-2y-6+2=0

We add all the numbers together, and all the variables

-16y-4=0

We move all terms containing y to the left, all other terms to the right

-16y=4

y=4/-16

y=-1/4

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