-2(8y-4)+7y=3(y+6)

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Solution for -2(8y-4)+7y=3(y+6) equation: 



-2(8y-4)+7y=3(y+6)

We move all terms to the left:

-2(8y-4)+7y-(3(y+6))=0

We add all the numbers together, and all the variables

7y-2(8y-4)-(3(y+6))=0

We multiply parentheses

7y-16y-(3(y+6))+8=0



We calculate terms in parentheses: -(3(y+6)), so:

3(y+6)

We multiply parentheses

3y+18

Back to the equation:

-(3y+18)



We add all the numbers together, and all the variables

-9y-(3y+18)+8=0

We get rid of parentheses

-9y-3y-18+8=0

We add all the numbers together, and all the variables

-12y-10=0

We move all terms containing y to the left, all other terms to the right

-12y=10

y=10/-12

y=-5/6

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