-2(8y-5)+4y=4(y+3)

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Solution for -2(8y-5)+4y=4(y+3) equation: 



-2(8y-5)+4y=4(y+3)

We move all terms to the left:

-2(8y-5)+4y-(4(y+3))=0

We add all the numbers together, and all the variables

4y-2(8y-5)-(4(y+3))=0

We multiply parentheses

4y-16y-(4(y+3))+10=0



We calculate terms in parentheses: -(4(y+3)), so:

4(y+3)

We multiply parentheses

4y+12

Back to the equation:

-(4y+12)



We add all the numbers together, and all the variables

-12y-(4y+12)+10=0

We get rid of parentheses

-12y-4y-12+10=0

We add all the numbers together, and all the variables

-16y-2=0

We move all terms containing y to the left, all other terms to the right

-16y=2

y=2/-16

y=-1/8

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