-2(8y-7)+4y=2(y+2)

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Solution for -2(8y-7)+4y=2(y+2) equation:



-2(8y-7)+4y=2(y+2)
We move all terms to the left:
-2(8y-7)+4y-(2(y+2))=0
We add all the numbers together, and all the variables
4y-2(8y-7)-(2(y+2))=0
We multiply parentheses
4y-16y-(2(y+2))+14=0
We calculate terms in parentheses: -(2(y+2)), so:
2(y+2)
We multiply parentheses
2y+4
Back to the equation:
-(2y+4)
We add all the numbers together, and all the variables
-12y-(2y+4)+14=0
We get rid of parentheses
-12y-2y-4+14=0
We add all the numbers together, and all the variables
-14y+10=0
We move all terms containing y to the left, all other terms to the right
-14y=-10
y=-10/-14
y=5/7

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