-2(8y-7)+4y=2(y+2)

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Solution for -2(8y-7)+4y=2(y+2) equation: 



-2(8y-7)+4y=2(y+2)

We move all terms to the left:

-2(8y-7)+4y-(2(y+2))=0

We add all the numbers together, and all the variables

4y-2(8y-7)-(2(y+2))=0

We multiply parentheses

4y-16y-(2(y+2))+14=0



We calculate terms in parentheses: -(2(y+2)), so:

2(y+2)

We multiply parentheses

2y+4

Back to the equation:

-(2y+4)



We add all the numbers together, and all the variables

-12y-(2y+4)+14=0

We get rid of parentheses

-12y-2y-4+14=0

We add all the numbers together, and all the variables

-14y+10=0

We move all terms containing y to the left, all other terms to the right

-14y=-10

y=-10/-14

y=5/7

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