-2(9-u)-u=2(u-2)-2

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Solution for -2(9-u)-u=2(u-2)-2 equation: 



-2(9-u)-u=2(u-2)-2

We move all terms to the left:

-2(9-u)-u-(2(u-2)-2)=0

We add all the numbers together, and all the variables

-2(-1u+9)-u-(2(u-2)-2)=0

We add all the numbers together, and all the variables

-1u-2(-1u+9)-(2(u-2)-2)=0

We multiply parentheses

-1u+2u-(2(u-2)-2)-18=0



We calculate terms in parentheses: -(2(u-2)-2), so:

2(u-2)-2

We multiply parentheses

2u-4-2

We add all the numbers together, and all the variables

2u-6

Back to the equation:

-(2u-6)



We add all the numbers together, and all the variables

u-(2u-6)-18=0

We get rid of parentheses

u-2u+6-18=0

We add all the numbers together, and all the variables

-1u-12=0

We move all terms containing u to the left, all other terms to the right

-u=12

u=12/-1

u=-12

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