-2(9-u)-u=2(u-2)-2

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Solution for -2(9-u)-u=2(u-2)-2 equation:



-2(9-u)-u=2(u-2)-2
We move all terms to the left:
-2(9-u)-u-(2(u-2)-2)=0
We add all the numbers together, and all the variables
-2(-1u+9)-u-(2(u-2)-2)=0
We add all the numbers together, and all the variables
-1u-2(-1u+9)-(2(u-2)-2)=0
We multiply parentheses
-1u+2u-(2(u-2)-2)-18=0
We calculate terms in parentheses: -(2(u-2)-2), so:
2(u-2)-2
We multiply parentheses
2u-4-2
We add all the numbers together, and all the variables
2u-6
Back to the equation:
-(2u-6)
We add all the numbers together, and all the variables
u-(2u-6)-18=0
We get rid of parentheses
u-2u+6-18=0
We add all the numbers together, and all the variables
-1u-12=0
We move all terms containing u to the left, all other terms to the right
-u=12
u=12/-1
u=-12

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