-2(9u-4)+9u=3(u+6)

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Solution for -2(9u-4)+9u=3(u+6) equation:



-2(9u-4)+9u=3(u+6)
We move all terms to the left:
-2(9u-4)+9u-(3(u+6))=0
We add all the numbers together, and all the variables
9u-2(9u-4)-(3(u+6))=0
We multiply parentheses
9u-18u-(3(u+6))+8=0
We calculate terms in parentheses: -(3(u+6)), so:
3(u+6)
We multiply parentheses
3u+18
Back to the equation:
-(3u+18)
We add all the numbers together, and all the variables
-9u-(3u+18)+8=0
We get rid of parentheses
-9u-3u-18+8=0
We add all the numbers together, and all the variables
-12u-10=0
We move all terms containing u to the left, all other terms to the right
-12u=10
u=10/-12
u=-5/6

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