-2(a-4)2a=6+2a

Solution for -2(a-4)2a=6+2a equation:

-2(a-4)2a=6+2a

We move all terms to the left:

-2(a-4)2a-(6+2a)=0

We add all the numbers together, and all the variables

-2(a-4)2a-(2a+6)=0

We multiply parentheses

-4a^2+16a-(2a+6)=0

We get rid of parentheses

-4a^2+16a-2a-6=0

We add all the numbers together, and all the variables

-4a^2+14a-6=0

a = -4; b = 14; c = -6;
Δ = b2-4ac
Δ = 142-4·(-4)·(-6)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-10}{2*-4}=\frac{-24}{-8}
=+3
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+10}{2*-4}=\frac{-4}{-8}
=1/2
$