-2(b+1)+6b=-2((b-5)

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Solution for -2(b+1)+6b=-2((b-5) equation: 



-2(b+1)+6b=-2((b-5)

We move all terms to the left:

-2(b+1)+6b-(-2((b-5))=0

We add all the numbers together, and all the variables

6b-2(b+1)-(-2((b-5))=0

We multiply parentheses

6b-2b-(-2((b-5))-2=0

We add all the numbers together, and all the variables

4b-(-2((b-5))-2=0

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