-2(b+2)=12+2(12+4b)

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Solution for -2(b+2)=12+2(12+4b) equation: 



-2(b+2)=12+2(12+4b)

We move all terms to the left:

-2(b+2)-(12+2(12+4b))=0

We add all the numbers together, and all the variables

-2(b+2)-(12+2(4b+12))=0

We multiply parentheses

-2b-(12+2(4b+12))-4=0



We calculate terms in parentheses: -(12+2(4b+12)), so:

12+2(4b+12)

determiningTheFunctionDomain
2(4b+12)+12

We multiply parentheses

8b+24+12

We add all the numbers together, and all the variables

8b+36

Back to the equation:

-(8b+36)



We get rid of parentheses

-2b-8b-36-4=0

We add all the numbers together, and all the variables

-10b-40=0

We move all terms containing b to the left, all other terms to the right

-10b=40

b=40/-10

b=-4

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