-2(b-3)+8=10

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Solution for -2(b-3)+8=10 equation: 



-2(b-3)+8=10

We move all terms to the left:

-2(b-3)+8-(10)=0

We add all the numbers together, and all the variables

-2(b-3)-2=0

We multiply parentheses

-2b+6-2=0

We add all the numbers together, and all the variables

-2b+4=0

We move all terms containing b to the left, all other terms to the right

-2b=-4

b=-4/-2

b=+2

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