-2(b-3)-2b=3(-4b+2)

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Solution for -2(b-3)-2b=3(-4b+2) equation: 



-2(b-3)-2b=3(-4b+2)

We move all terms to the left:

-2(b-3)-2b-(3(-4b+2))=0

We add all the numbers together, and all the variables

-2b-2(b-3)-(3(-4b+2))=0

We multiply parentheses

-2b-2b-(3(-4b+2))+6=0



We calculate terms in parentheses: -(3(-4b+2)), so:

3(-4b+2)

We multiply parentheses

-12b+6

Back to the equation:

-(-12b+6)



We add all the numbers together, and all the variables

-4b-(-12b+6)+6=0

We get rid of parentheses

-4b+12b-6+6=0

We add all the numbers together, and all the variables

8b=0

b=0/8

b=0

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