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-2(b-4)=1/2(b+4)
We move all terms to the left:
-2(b-4)-(1/2(b+4))=0
Domain of the equation: 2(b+4))!=0We multiply parentheses
b∈R
-2b-(1/2(b+4))+8=0
We multiply all the terms by the denominator
-2b*2(b+4))-(1+8*2(b+4))=0
Wy multiply elements
-4b^2(b+16b(b=0
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