-2(b-5)=-2b-2+12

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Solution for -2(b-5)=-2b-2+12 equation: 



-2(b-5)=-2b-2+12

We move all terms to the left:

-2(b-5)-(-2b-2+12)=0

We add all the numbers together, and all the variables

-2(b-5)-(-2b+10)=0

We multiply parentheses

-2b-(-2b+10)+10=0

We get rid of parentheses

-2b+2b-10+10=0

We add all the numbers together, and all the variables

=0

b=0/1

b=0

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