-2(c+2)=-3(c-5)

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Solution for -2(c+2)=-3(c-5) equation: 



-2(c+2)=-3(c-5)

We move all terms to the left:

-2(c+2)-(-3(c-5))=0

We multiply parentheses

-2c-(-3(c-5))-4=0



We calculate terms in parentheses: -(-3(c-5)), so:

-3(c-5)

We multiply parentheses

-3c+15

Back to the equation:

-(-3c+15)



We get rid of parentheses

-2c+3c-15-4=0

We add all the numbers together, and all the variables

c-19=0

We move all terms containing c to the left, all other terms to the right

c=19

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