-2(c-11)+6=-8c-2

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Solution for -2(c-11)+6=-8c-2 equation: 



-2(c-11)+6=-8c-2

We move all terms to the left:

-2(c-11)+6-(-8c-2)=0

We multiply parentheses

-2c-(-8c-2)+22+6=0

We get rid of parentheses

-2c+8c+2+22+6=0

We add all the numbers together, and all the variables

6c+30=0

We move all terms containing c to the left, all other terms to the right

6c=-30

c=-30/6

c=-5

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