-2(c-11)=3(c+2)

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Solution for -2(c-11)=3(c+2) equation: 



-2(c-11)=3(c+2)

We move all terms to the left:

-2(c-11)-(3(c+2))=0

We multiply parentheses

-2c-(3(c+2))+22=0



We calculate terms in parentheses: -(3(c+2)), so:

3(c+2)

We multiply parentheses

3c+6

Back to the equation:

-(3c+6)



We get rid of parentheses

-2c-3c-6+22=0

We add all the numbers together, and all the variables

-5c+16=0

We move all terms containing c to the left, all other terms to the right

-5c=-16

c=-16/-5

c=3+1/5

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