-2(c-4)-(3c-2)=-2-2(3c+1)

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Solution for -2(c-4)-(3c-2)=-2-2(3c+1) equation: 



-2(c-4)-(3c-2)=-2-2(3c+1)

We move all terms to the left:

-2(c-4)-(3c-2)-(-2-2(3c+1))=0

We multiply parentheses

-2c-(3c-2)-(-2-2(3c+1))+8=0

We get rid of parentheses

-2c-3c-(-2-2(3c+1))+2+8=0



We calculate terms in parentheses: -(-2-2(3c+1)), so:

-2-2(3c+1)

determiningTheFunctionDomain
-2(3c+1)-2

We multiply parentheses

-6c-2-2

We add all the numbers together, and all the variables

-6c-4

Back to the equation:

-(-6c-4)



We add all the numbers together, and all the variables

-5c-(-6c-4)+10=0

We get rid of parentheses

-5c+6c+4+10=0

We add all the numbers together, and all the variables

c+14=0

We move all terms containing c to the left, all other terms to the right

c=-14

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