-2(c-5)=10-2c

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Solution for -2(c-5)=10-2c equation: 



-2(c-5)=10-2c

We move all terms to the left:

-2(c-5)-(10-2c)=0

We add all the numbers together, and all the variables

-2(c-5)-(-2c+10)=0

We multiply parentheses

-2c-(-2c+10)+10=0

We get rid of parentheses

-2c+2c-10+10=0

We add all the numbers together, and all the variables

=0

c=0/1

c=0

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