-2(i+5)+6=4(i+2)

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Solution for -2(i+5)+6=4(i+2) equation: 



-2(i+5)+6=4(i+2)

We move all terms to the left:

-2(i+5)+6-(4(i+2))=0

We multiply parentheses

-2i-(4(i+2))-10+6=0



We calculate terms in parentheses: -(4(i+2)), so:

4(i+2)

We multiply parentheses

4i+8

Back to the equation:

-(4i+8)



We add all the numbers together, and all the variables

-2i-(4i+8)-4=0

We get rid of parentheses

-2i-4i-8-4=0

We add all the numbers together, and all the variables

-6i-12=0

We move all terms containing i to the left, all other terms to the right

-6i=12

i=12/-6

i=-2

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