-2(j+-1)+3(j+4)=8

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Solution for -2(j+-1)+3(j+4)=8 equation: 



-2(j+-1)+3(j+4)=8

We move all terms to the left:

-2(j+-1)+3(j+4)-(8)=0

We add all the numbers together, and all the variables

-2(j-1)+3(j+4)-8=0

We multiply parentheses

-2j+3j+2+12-8=0

We add all the numbers together, and all the variables

j+6=0

We move all terms containing j to the left, all other terms to the right

j=-6

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