-2(k+2)-k-6=-3(k+5)+5

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Solution for -2(k+2)-k-6=-3(k+5)+5 equation: 



-2(k+2)-k-6=-3(k+5)+5

We move all terms to the left:

-2(k+2)-k-6-(-3(k+5)+5)=0

We add all the numbers together, and all the variables

-1k-2(k+2)-(-3(k+5)+5)-6=0

We multiply parentheses

-1k-2k-(-3(k+5)+5)-4-6=0



We calculate terms in parentheses: -(-3(k+5)+5), so:

-3(k+5)+5

We multiply parentheses

-3k-15+5

We add all the numbers together, and all the variables

-3k-10

Back to the equation:

-(-3k-10)



We add all the numbers together, and all the variables

-3k-(-3k-10)-10=0

We get rid of parentheses

-3k+3k+10-10=0

We add all the numbers together, and all the variables

=0

k=0/1

k=0

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