-2(k+2)-k-6=-3(k+5)+5

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Solution for -2(k+2)-k-6=-3(k+5)+5 equation:



-2(k+2)-k-6=-3(k+5)+5
We move all terms to the left:
-2(k+2)-k-6-(-3(k+5)+5)=0
We add all the numbers together, and all the variables
-1k-2(k+2)-(-3(k+5)+5)-6=0
We multiply parentheses
-1k-2k-(-3(k+5)+5)-4-6=0
We calculate terms in parentheses: -(-3(k+5)+5), so:
-3(k+5)+5
We multiply parentheses
-3k-15+5
We add all the numbers together, and all the variables
-3k-10
Back to the equation:
-(-3k-10)
We add all the numbers together, and all the variables
-3k-(-3k-10)-10=0
We get rid of parentheses
-3k+3k+10-10=0
We add all the numbers together, and all the variables
=0
k=0/1
k=0

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