-2(k+3)=2(k-1)

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Solution for -2(k+3)=2(k-1) equation: 



-2(k+3)=2(k-1)

We move all terms to the left:

-2(k+3)-(2(k-1))=0

We multiply parentheses

-2k-(2(k-1))-6=0



We calculate terms in parentheses: -(2(k-1)), so:

2(k-1)

We multiply parentheses

2k-2

Back to the equation:

-(2k-2)



We get rid of parentheses

-2k-2k+2-6=0

We add all the numbers together, and all the variables

-4k-4=0

We move all terms containing k to the left, all other terms to the right

-4k=4

k=4/-4

k=-1

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