-2(k-3)=(-k+4)-2

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Solution for -2(k-3)=(-k+4)-2 equation: 



-2(k-3)=(-k+4)-2

We move all terms to the left:

-2(k-3)-((-k+4)-2)=0

We add all the numbers together, and all the variables

-2(k-3)-((-1k+4)-2)=0

We multiply parentheses

-2k-((-1k+4)-2)+6=0



We calculate terms in parentheses: -((-1k+4)-2), so:

(-1k+4)-2

We get rid of parentheses

-1k+4-2

We add all the numbers together, and all the variables

-1k+2

Back to the equation:

-(-1k+2)



We get rid of parentheses

-2k+1k-2+6=0

We add all the numbers together, and all the variables

-1k+4=0

We move all terms containing k to the left, all other terms to the right

-k=-4

k=-4/-1

k=+4

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