-2(k-6)+8=2(1+2k

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Solution for -2(k-6)+8=2(1+2k equation: 



-2(k-6)+8=2(1+2k

We move all terms to the left:

-2(k-6)+8-(2(1+2k)=0

We add all the numbers together, and all the variables

-2(k-6)-(2(2k+1)+8=0

We multiply parentheses

-2k-(2(2k+1)+8+12=0

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