-2(k-6)+8=2(1+2k)

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Solution for -2(k-6)+8=2(1+2k) equation: 



-2(k-6)+8=2(1+2k)

We move all terms to the left:

-2(k-6)+8-(2(1+2k))=0

We add all the numbers together, and all the variables

-2(k-6)-(2(2k+1))+8=0

We multiply parentheses

-2k-(2(2k+1))+12+8=0



We calculate terms in parentheses: -(2(2k+1)), so:

2(2k+1)

We multiply parentheses

4k+2

Back to the equation:

-(4k+2)



We add all the numbers together, and all the variables

-2k-(4k+2)+20=0

We get rid of parentheses

-2k-4k-2+20=0

We add all the numbers together, and all the variables

-6k+18=0

We move all terms containing k to the left, all other terms to the right

-6k=-18

k=-18/-6

k=+3

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