-2(n+4)-n=3n-14

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Solution for -2(n+4)-n=3n-14 equation: 



-2(n+4)-n=3n-14

We move all terms to the left:

-2(n+4)-n-(3n-14)=0

We add all the numbers together, and all the variables

-1n-2(n+4)-(3n-14)=0

We multiply parentheses

-1n-2n-(3n-14)-8=0

We get rid of parentheses

-1n-2n-3n+14-8=0

We add all the numbers together, and all the variables

-6n+6=0

We move all terms containing n to the left, all other terms to the right

-6n=-6

n=-6/-6

n=1

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