-2(n+6)+3(4n+12)=64

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Solution for -2(n+6)+3(4n+12)=64 equation: 



-2(n+6)+3(4n+12)=64

We move all terms to the left:

-2(n+6)+3(4n+12)-(64)=0

We multiply parentheses

-2n+12n-12+36-64=0

We add all the numbers together, and all the variables

10n-40=0

We move all terms containing n to the left, all other terms to the right

10n=40

n=40/10

n=4

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