-2(n-2)+6n=2(n+5)

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Solution for -2(n-2)+6n=2(n+5) equation: 



-2(n-2)+6n=2(n+5)

We move all terms to the left:

-2(n-2)+6n-(2(n+5))=0

We add all the numbers together, and all the variables

6n-2(n-2)-(2(n+5))=0

We multiply parentheses

6n-2n-(2(n+5))+4=0



We calculate terms in parentheses: -(2(n+5)), so:

2(n+5)

We multiply parentheses

2n+10

Back to the equation:

-(2n+10)



We add all the numbers together, and all the variables

4n-(2n+10)+4=0

We get rid of parentheses

4n-2n-10+4=0

We add all the numbers together, and all the variables

2n-6=0

We move all terms containing n to the left, all other terms to the right

2n=6

n=6/2

n=3

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