-2(n-3)=-22+2n

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Solution for -2(n-3)=-22+2n equation: 



-2(n-3)=-22+2n

We move all terms to the left:

-2(n-3)-(-22+2n)=0

We add all the numbers together, and all the variables

-2(n-3)-(2n-22)=0

We multiply parentheses

-2n-(2n-22)+6=0

We get rid of parentheses

-2n-2n+22+6=0

We add all the numbers together, and all the variables

-4n+28=0

We move all terms containing n to the left, all other terms to the right

-4n=-28

n=-28/-4

n=+7

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