-2(n-3)=2n+22

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Solution for -2(n-3)=2n+22 equation: 



-2(n-3)=2n+22

We move all terms to the left:

-2(n-3)-(2n+22)=0

We multiply parentheses

-2n-(2n+22)+6=0

We get rid of parentheses

-2n-2n-22+6=0

We add all the numbers together, and all the variables

-4n-16=0

We move all terms containing n to the left, all other terms to the right

-4n=16

n=16/-4

n=-4

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