-2(n-4)-(3n-1)=-2=2n-1

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Solution for -2(n-4)-(3n-1)=-2=2n-1 equation: 



-2(n-4)-(3n-1)=-2=2n-1

We move all terms to the left:

-2(n-4)-(3n-1)-(-2)=0

We add all the numbers together, and all the variables

-2(n-4)-(3n-1)+2=0

We multiply parentheses

-2n-(3n-1)+8+2=0

We get rid of parentheses

-2n-3n+1+8+2=0

We add all the numbers together, and all the variables

-5n+11=0

We move all terms containing n to the left, all other terms to the right

-5n=-11

n=-11/-5

n=2+1/5

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