-2(n-5)=2(n+3)-4n

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Solution for -2(n-5)=2(n+3)-4n equation:



-2(n-5)=2(n+3)-4n
We move all terms to the left:
-2(n-5)-(2(n+3)-4n)=0
We multiply parentheses
-2n-(2(n+3)-4n)+10=0
We calculate terms in parentheses: -(2(n+3)-4n), so:
2(n+3)-4n
We add all the numbers together, and all the variables
-4n+2(n+3)
We multiply parentheses
-4n+2n+6
We add all the numbers together, and all the variables
-2n+6
Back to the equation:
-(-2n+6)
We get rid of parentheses
-2n+2n-6+10=0
We add all the numbers together, and all the variables
4!=0
There is no solution for this equation

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