-2(t+2)+5t=2(r-4)-6

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Solution for -2(t+2)+5t=2(r-4)-6 equation:


Simplifying
-2(t + 2) + 5t = 2(r + -4) + -6

Reorder the terms:
-2(2 + t) + 5t = 2(r + -4) + -6
(2 * -2 + t * -2) + 5t = 2(r + -4) + -6
(-4 + -2t) + 5t = 2(r + -4) + -6

Combine like terms: -2t + 5t = 3t
-4 + 3t = 2(r + -4) + -6

Reorder the terms:
-4 + 3t = 2(-4 + r) + -6
-4 + 3t = (-4 * 2 + r * 2) + -6
-4 + 3t = (-8 + 2r) + -6

Reorder the terms:
-4 + 3t = -8 + -6 + 2r

Combine like terms: -8 + -6 = -14
-4 + 3t = -14 + 2r

Solving
-4 + 3t = -14 + 2r

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + 3t = -14 + 4 + 2r

Combine like terms: -4 + 4 = 0
0 + 3t = -14 + 4 + 2r
3t = -14 + 4 + 2r

Combine like terms: -14 + 4 = -10
3t = -10 + 2r

Divide each side by '3'.
t = -3.333333333 + 0.6666666667r

Simplifying
t = -3.333333333 + 0.6666666667r

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