-2(t+3)-t=-t-4(t+2)

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Solution for -2(t+3)-t=-t-4(t+2) equation: 



-2(t+3)-t=-t-4(t+2)

We move all terms to the left:

-2(t+3)-t-(-t-4(t+2))=0

We add all the numbers together, and all the variables

-1t-2(t+3)-(-t-4(t+2))=0

We multiply parentheses

-1t-2t-(-t-4(t+2))-6=0



We calculate terms in parentheses: -(-t-4(t+2)), so:

-t-4(t+2)

We add all the numbers together, and all the variables

-1t-4(t+2)

We multiply parentheses

-1t-4t-8

We add all the numbers together, and all the variables

-5t-8

Back to the equation:

-(-5t-8)



We add all the numbers together, and all the variables

-3t-(-5t-8)-6=0

We get rid of parentheses

-3t+5t+8-6=0

We add all the numbers together, and all the variables

2t+2=0

We move all terms containing t to the left, all other terms to the right

2t=-2

t=-2/2

t=-1

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