-2(t-2)-(t+2)=5

Solution for -2(t-2)-(t+2)=5 equation:

Simplifying
-2(t + -2) + -1(t + 2) = 5

Reorder the terms:
-2(-2 + t) + -1(t + 2) = 5
(-2 * -2 + t * -2) + -1(t + 2) = 5
(4 + -2t) + -1(t + 2) = 5

Reorder the terms:
4 + -2t + -1(2 + t) = 5
4 + -2t + (2 * -1 + t * -1) = 5
4 + -2t + (-2 + -1t) = 5

Reorder the terms:
4 + -2 + -2t + -1t = 5

Combine like terms: 4 + -2 = 2
2 + -2t + -1t = 5

Combine like terms: -2t + -1t = -3t
2 + -3t = 5

Solving
2 + -3t = 5

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -3t = 5 + -2

Combine like terms: 2 + -2 = 0
0 + -3t = 5 + -2
-3t = 5 + -2

Combine like terms: 5 + -2 = 3
-3t = 3

Divide each side by '-3'.
t = -1

Simplifying
t = -1