-2(u+1)=3u-3+2(2u+2)

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Solution for -2(u+1)=3u-3+2(2u+2) equation:



-2(u+1)=3u-3+2(2u+2)
We move all terms to the left:
-2(u+1)-(3u-3+2(2u+2))=0
We multiply parentheses
-2u-(3u-3+2(2u+2))-2=0
We calculate terms in parentheses: -(3u-3+2(2u+2)), so:
3u-3+2(2u+2)
determiningTheFunctionDomain 3u+2(2u+2)-3
We multiply parentheses
3u+4u+4-3
We add all the numbers together, and all the variables
7u+1
Back to the equation:
-(7u+1)
We get rid of parentheses
-2u-7u-1-2=0
We add all the numbers together, and all the variables
-9u-3=0
We move all terms containing u to the left, all other terms to the right
-9u=3
u=3/-9
u=-1/3

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