-2(u+1)=4u-2+4(2u+2)

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Solution for -2(u+1)=4u-2+4(2u+2) equation: 



-2(u+1)=4u-2+4(2u+2)

We move all terms to the left:

-2(u+1)-(4u-2+4(2u+2))=0

We multiply parentheses

-2u-(4u-2+4(2u+2))-2=0



We calculate terms in parentheses: -(4u-2+4(2u+2)), so:

4u-2+4(2u+2)

determiningTheFunctionDomain
4u+4(2u+2)-2

We multiply parentheses

4u+8u+8-2

We add all the numbers together, and all the variables

12u+6

Back to the equation:

-(12u+6)



We get rid of parentheses

-2u-12u-6-2=0

We add all the numbers together, and all the variables

-14u-8=0

We move all terms containing u to the left, all other terms to the right

-14u=8

u=8/-14

u=-4/7

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