-2(u+1)=u-2+3(2u+5)

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Solution for -2(u+1)=u-2+3(2u+5) equation: 



-2(u+1)=u-2+3(2u+5)

We move all terms to the left:

-2(u+1)-(u-2+3(2u+5))=0

We multiply parentheses

-2u-(u-2+3(2u+5))-2=0



We calculate terms in parentheses: -(u-2+3(2u+5)), so:

u-2+3(2u+5)

determiningTheFunctionDomain
u+3(2u+5)-2

We multiply parentheses

u+6u+15-2

We add all the numbers together, and all the variables

7u+13

Back to the equation:

-(7u+13)



We get rid of parentheses

-2u-7u-13-2=0

We add all the numbers together, and all the variables

-9u-15=0

We move all terms containing u to the left, all other terms to the right

-9u=15

u=15/-9

u=-1+2/3

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