-2(u+2)=2(3+u)-4u-10

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Solution for -2(u+2)=2(3+u)-4u-10 equation: 



-2(u+2)=2(3+u)-4u-10

We move all terms to the left:

-2(u+2)-(2(3+u)-4u-10)=0

We add all the numbers together, and all the variables

-2(u+2)-(2(u+3)-4u-10)=0

We multiply parentheses

-2u-(2(u+3)-4u-10)-4=0



We calculate terms in parentheses: -(2(u+3)-4u-10), so:

2(u+3)-4u-10

We add all the numbers together, and all the variables

-4u+2(u+3)-10

We multiply parentheses

-4u+2u+6-10

We add all the numbers together, and all the variables

-2u-4

Back to the equation:

-(-2u-4)



We get rid of parentheses

-2u+2u+4-4=0

We add all the numbers together, and all the variables

=0

u=0/1

u=0

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