-2(u+2)=2u-8+4(2u+5)

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Solution for -2(u+2)=2u-8+4(2u+5) equation:



-2(u+2)=2u-8+4(2u+5)
We move all terms to the left:
-2(u+2)-(2u-8+4(2u+5))=0
We multiply parentheses
-2u-(2u-8+4(2u+5))-4=0
We calculate terms in parentheses: -(2u-8+4(2u+5)), so:
2u-8+4(2u+5)
determiningTheFunctionDomain 2u+4(2u+5)-8
We multiply parentheses
2u+8u+20-8
We add all the numbers together, and all the variables
10u+12
Back to the equation:
-(10u+12)
We get rid of parentheses
-2u-10u-12-4=0
We add all the numbers together, and all the variables
-12u-16=0
We move all terms containing u to the left, all other terms to the right
-12u=16
u=16/-12
u=-1+1/3

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