-2(u+2)=2u-8+4(2u+5)

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Solution for -2(u+2)=2u-8+4(2u+5) equation: 



-2(u+2)=2u-8+4(2u+5)

We move all terms to the left:

-2(u+2)-(2u-8+4(2u+5))=0

We multiply parentheses

-2u-(2u-8+4(2u+5))-4=0



We calculate terms in parentheses: -(2u-8+4(2u+5)), so:

2u-8+4(2u+5)

determiningTheFunctionDomain
2u+4(2u+5)-8

We multiply parentheses

2u+8u+20-8

We add all the numbers together, and all the variables

10u+12

Back to the equation:

-(10u+12)



We get rid of parentheses

-2u-10u-12-4=0

We add all the numbers together, and all the variables

-12u-16=0

We move all terms containing u to the left, all other terms to the right

-12u=16

u=16/-12

u=-1+1/3

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