-2(u+2)=7u-6+3(2u+4)

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Solution for -2(u+2)=7u-6+3(2u+4) equation: 



-2(u+2)=7u-6+3(2u+4)

We move all terms to the left:

-2(u+2)-(7u-6+3(2u+4))=0

We multiply parentheses

-2u-(7u-6+3(2u+4))-4=0



We calculate terms in parentheses: -(7u-6+3(2u+4)), so:

7u-6+3(2u+4)

determiningTheFunctionDomain
7u+3(2u+4)-6

We multiply parentheses

7u+6u+12-6

We add all the numbers together, and all the variables

13u+6

Back to the equation:

-(13u+6)



We get rid of parentheses

-2u-13u-6-4=0

We add all the numbers together, and all the variables

-15u-10=0

We move all terms containing u to the left, all other terms to the right

-15u=10

u=10/-15

u=-2/3

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