-2(u+3)=2u-4+2(4u+6)

Solution for -2(u+3)=2u-4+2(4u+6) equation:

-2(u+3)=2u-4+2(4u+6)

We move all terms to the left:

-2(u+3)-(2u-4+2(4u+6))=0

We multiply parentheses

-2u-(2u-4+2(4u+6))-6=0


We calculate terms in parentheses: -(2u-4+2(4u+6)), so:

2u-4+2(4u+6)

determiningTheFunctionDomain
2u+2(4u+6)-4

We multiply parentheses

2u+8u+12-4

We add all the numbers together, and all the variables

10u+8

Back to the equation:

-(10u+8)


We get rid of parentheses

-2u-10u-8-6=0

We add all the numbers together, and all the variables

-12u-14=0

We move all terms containing u to the left, all other terms to the right

-12u=14

u=14/-12

u=-1+1/6