-2(u+3)=5u-4+3(3u+2)

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Solution for -2(u+3)=5u-4+3(3u+2) equation: 



-2(u+3)=5u-4+3(3u+2)

We move all terms to the left:

-2(u+3)-(5u-4+3(3u+2))=0

We multiply parentheses

-2u-(5u-4+3(3u+2))-6=0



We calculate terms in parentheses: -(5u-4+3(3u+2)), so:

5u-4+3(3u+2)

determiningTheFunctionDomain
5u+3(3u+2)-4

We multiply parentheses

5u+9u+6-4

We add all the numbers together, and all the variables

14u+2

Back to the equation:

-(14u+2)



We get rid of parentheses

-2u-14u-2-6=0

We add all the numbers together, and all the variables

-16u-8=0

We move all terms containing u to the left, all other terms to the right

-16u=8

u=8/-16

u=-1/2

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