-2(u+4)=2u-4+2(3u+6)

Solution for -2(u+4)=2u-4+2(3u+6) equation:

-2(u+4)=2u-4+2(3u+6)

We move all terms to the left:

-2(u+4)-(2u-4+2(3u+6))=0

We multiply parentheses

-2u-(2u-4+2(3u+6))-8=0


We calculate terms in parentheses: -(2u-4+2(3u+6)), so:

2u-4+2(3u+6)

determiningTheFunctionDomain
2u+2(3u+6)-4

We multiply parentheses

2u+6u+12-4

We add all the numbers together, and all the variables

8u+8

Back to the equation:

-(8u+8)


We get rid of parentheses

-2u-8u-8-8=0

We add all the numbers together, and all the variables

-10u-16=0

We move all terms containing u to the left, all other terms to the right

-10u=16

u=16/-10

u=-1+3/5