-2(u+4)=2u-4+2(3u+6)

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Solution for -2(u+4)=2u-4+2(3u+6) equation:



-2(u+4)=2u-4+2(3u+6)
We move all terms to the left:
-2(u+4)-(2u-4+2(3u+6))=0
We multiply parentheses
-2u-(2u-4+2(3u+6))-8=0
We calculate terms in parentheses: -(2u-4+2(3u+6)), so:
2u-4+2(3u+6)
determiningTheFunctionDomain 2u+2(3u+6)-4
We multiply parentheses
2u+6u+12-4
We add all the numbers together, and all the variables
8u+8
Back to the equation:
-(8u+8)
We get rid of parentheses
-2u-8u-8-8=0
We add all the numbers together, and all the variables
-10u-16=0
We move all terms containing u to the left, all other terms to the right
-10u=16
u=16/-10
u=-1+3/5

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