-2(u+4)=2u-9+3(2u+2)

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Solution for -2(u+4)=2u-9+3(2u+2) equation: 



-2(u+4)=2u-9+3(2u+2)

We move all terms to the left:

-2(u+4)-(2u-9+3(2u+2))=0

We multiply parentheses

-2u-(2u-9+3(2u+2))-8=0



We calculate terms in parentheses: -(2u-9+3(2u+2)), so:

2u-9+3(2u+2)

determiningTheFunctionDomain
2u+3(2u+2)-9

We multiply parentheses

2u+6u+6-9

We add all the numbers together, and all the variables

8u-3

Back to the equation:

-(8u-3)



We get rid of parentheses

-2u-8u+3-8=0

We add all the numbers together, and all the variables

-10u-5=0

We move all terms containing u to the left, all other terms to the right

-10u=5

u=5/-10

u=-1/2

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