-2(u+4)=6u-2+2(3u+5)

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Solution for -2(u+4)=6u-2+2(3u+5) equation: 



-2(u+4)=6u-2+2(3u+5)

We move all terms to the left:

-2(u+4)-(6u-2+2(3u+5))=0

We multiply parentheses

-2u-(6u-2+2(3u+5))-8=0



We calculate terms in parentheses: -(6u-2+2(3u+5)), so:

6u-2+2(3u+5)

determiningTheFunctionDomain
6u+2(3u+5)-2

We multiply parentheses

6u+6u+10-2

We add all the numbers together, and all the variables

12u+8

Back to the equation:

-(12u+8)



We get rid of parentheses

-2u-12u-8-8=0

We add all the numbers together, and all the variables

-14u-16=0

We move all terms containing u to the left, all other terms to the right

-14u=16

u=16/-14

u=-1+1/7

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