-2(u+6)=6u-5+2(2u+1)

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Solution for -2(u+6)=6u-5+2(2u+1) equation: 



-2(u+6)=6u-5+2(2u+1)

We move all terms to the left:

-2(u+6)-(6u-5+2(2u+1))=0

We multiply parentheses

-2u-(6u-5+2(2u+1))-12=0



We calculate terms in parentheses: -(6u-5+2(2u+1)), so:

6u-5+2(2u+1)

determiningTheFunctionDomain
6u+2(2u+1)-5

We multiply parentheses

6u+4u+2-5

We add all the numbers together, and all the variables

10u-3

Back to the equation:

-(10u-3)



We get rid of parentheses

-2u-10u+3-12=0

We add all the numbers together, and all the variables

-12u-9=0

We move all terms containing u to the left, all other terms to the right

-12u=9

u=9/-12

u=-3/4

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