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-2(v+1)+5v=3(v+1)
We move all terms to the left:
-2(v+1)+5v-(3(v+1))=0
We add all the numbers together, and all the variables
5v-2(v+1)-(3(v+1))=0
We multiply parentheses
5v-2v-(3(v+1))-2=0
We calculate terms in parentheses: -(3(v+1)), so:We add all the numbers together, and all the variables
3(v+1)
We multiply parentheses
3v+3
Back to the equation:
-(3v+3)
3v-(3v+3)-2=0
We get rid of parentheses
3v-3v-3-2=0
We add all the numbers together, and all the variables
-5!=0
There is no solution for this equation
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